view test/script/basic/JDK-8068903.js @ 1400:6e41fdc6acdf

8068901: Surprising behavior with more than one functional interface on a class 8068903: Can't invoke vararg @FunctionalInterface methods Reviewed-by: attila, hannesw
author sundar
date Tue, 01 Sep 2015 18:28:11 +0530
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/*
 * Copyright (c) 2015, Oracle and/or its affiliates. All rights reserved.
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
 * 
 * This code is free software; you can redistribute it and/or modify it
 * under the terms of the GNU General Public License version 2 only, as
 * published by the Free Software Foundation.
 * 
 * This code is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
 * accompanied this code).
 * 
 * You should have received a copy of the GNU General Public License version
 * 2 along with this work; if not, write to the Free Software Foundation,
 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
 * 
 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
 * or visit www.oracle.com if you need additional information or have any
 * questions.
 */

/**
 * JDK-8068903: Can't invoke vararg @FunctionalInterface methods
 *
 * @test
 * @run
 */

var vc = new (Java.type("jdk.nashorn.test.models.VarArgConsumer"))(
    function(x) {
        Assert.assertTrue(x.length == 3);
        Assert.assertTrue(x[0] == 1);
        Assert.assertTrue(x[1] == 2);
        Assert.assertTrue(x[2] == 3);
    }
);

vc(1, 2, 3);